If the line \(\frac{x + 1}{1}=\frac{y - m}{3}=\frac{z - 4}{6}\) lies in the plane 3x – 14y + 6z + 49 = 0, then the value of m is :(x + 1)/1 = (y - m)/3 = (z - 4)/6(A) 5 (B) 3 (C) 2 (D) -5

If the line \(\frac{x + 1}{1}=\frac{y - m}{3}=\frac{z - 4}{6}\) lies

1.	If the line \(\frac{x + 1}{1}=\frac{y - m}{3}=\frac{z - 4}{6}\) lies in the plane 3x – 14y + 6z + 49 = 0, then the value of m is :(x + 1)/1 = (y - m)/3 = (z - 4)/6(A) 5 (B) 3 (C) 2 (D) -5
Answer» Correct answer is (A) 5

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If the line \(\frac{x + 1}{1}=\frac{y - m}{3}=\frac{z - 4}{6}\) lies in the plane 3x – 14y + 6z + 49 = 0, then the value of m is :(x + 1)/1 = (y - m)/3 = (z - 4)/6(A) 5 (B) 3 (C) 2 (D) -5

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