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If the line `vecr = (2hati+ hatj - hatk) + lambda(hati+mhatj-2hatk)` is parallel to the plane `vecr.(2hati+hatj+mhatk) = 1` then find the value of m. |
Answer» Here, `vecb=hati+mhatj-2hatk` and `vecn = 2hati+hatj+mhatk` If line is parallel to the plane, then `sin theta = 0` `rArr vecb.vecn = 0` `rArr (hati+mhatj-2hatk).(2hati+hatj+mhatk) = 0` `rArr 2+m - 2 m = 0` `rArr m = 2`. |
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