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If the lines p(p2 + 1)x - y + q = 0 and (p2 + 1)2x + (p2 + 1)y + 2q = 0 are perpendicula to the same line, then find the vaue of p will be,1. 12. -13. 04. -2 |
Answer» Correct Answer - Option 2 : -1 Concept: The general equation of a line is y = mx + c -----(A) Where m is the slope and c is any constant.
Calculation: The given lines are, p(p2 + 1)x - y + q = 0 ------(i) and (p2 + 1)2x + (p2 + 1)y + 2q = 0 -------(ii) Slope of the lines (i) is, \(\frac{-p(p^2+1)}{-1}\) i.e, p(p2 + 1) Similarly slope of the line (ii) is, \(-\frac{(p^2+1)^2}{p^2+1}\) i.e, -(p2 +1) Since the given lines are perpendicular to the same line, therefore, these lines are parallel which gives the lines have equal slope. ⇒ p(p2 + 1) = -(p2 +1) ⇒ (p2 + 1) (p + 1) = 0 but p2 + 1 ≠ 0 ⇒ p + 1 = 0 ⇒ p = -1 |
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