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If the lines `(x-1)/2=(y+1)/3=(z-1)/4a n d(x-3)/1=(y-k)/2=z/1`intersect, then find thevalue of `kdot`A. `3/2`B. `9/2`C. `-2/9`D. `-3/2` |
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Answer» Correct Answer - B We know that the lies `(x-x_(1))/(l_(1))=(y-y_(1))/(m_(1))=(z-z_(1))/(n_(1))` and `(x-x_(2))/(l_(2))=(y-y_(2))/(m_(2))=(z-z_(2))/(n_(2))` Intersect if `|(x_(2)-x_(1),y_(2)-y_(1),z_(2)-z_(1)),(l_(1),m_(1),n_(1)),(l_(2),m_(2),n_(2))|=0` So given lines will intersect, if `|(3-1,k+1,0-1),(2,3,4),(l,2,1)|=0` `implies 2(3-8)-(k+1)(2-4)-(4-3)=0impliesk=9/2` |
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