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If the magnitude of intensity of electric field at a distance x on axial line and at a distance y on equatorial line on a given dipole are equal, then x : y is |
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Answer» `root(3)(2) :1` `E_(1) = (2krho)/x^(3)(therefore x GT gt a)` `E_(2) = (kp)/y^(3)` magnitude `(therefore y gt gt a)` But `E_(1) =E_(2)` `therefore (2kp)/x^(3) = (kp)/y^(3)` `therefore 2 = x^(3)/y^(3)` `therefore 2^(1//3) = x/y` |
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