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If the magnitudes of two vectors are 2 and 3 and magnitude of their scalar product is `2sqrt3` what is the angle between the vectors ? |
Answer» `A=2B=3 " "barAbarB=2sqrt3` `costheta(barAbarB)/(AB)` `costheta=(vecA.vecB)/(AB)=(2sqrt3)/(2xx3)=(1)/(sqrt3)` `theta=cos^(-1)((1)/(sqrt3))` |
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