1.

If the mass of neutron is 1.7xx10^(-27) kg , then the de-Broglie wavelength of neutron of energy 3 eV Is………(h=6.6xx10^(-34)JS)

Answer»

`1.4xx10^(-11)m`
`1.6xx10^(-10)m`
`1.65xx10^(-11)m`
`1.4xx10^(-10)m`

SOLUTION :`lambda=(h)/(SQRT(2mE))`
`=(6.6xx10^(-34))/(sqrt(2xx1.7xx10^(-27)xx3xx1.6xx10^(-19)))`
`=(6.6xx10^(-34))/(4.04xx10^(-23))`
`=1.63xx10^(-11)m`
`~~1.65xx10^(-11)m`(NEAREST value)


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