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If the mass of neutron is 1.7xx10^(-27) kg , then the de-Broglie wavelength of neutron of energy 3 eV Is………(h=6.6xx10^(-34)JS) |
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Answer» `1.4xx10^(-11)m` `=(6.6xx10^(-34))/(sqrt(2xx1.7xx10^(-27)xx3xx1.6xx10^(-19)))` `=(6.6xx10^(-34))/(4.04xx10^(-23))` `=1.63xx10^(-11)m` `~~1.65xx10^(-11)m`(NEAREST value) |
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