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If the masses of two bodies are quadrupled and the distance between their centres is doubled, then how many times the force of gravitation between them will be changed ? |
Answer» `F_(1)=(Gm_(1)m_(2))/(r^(2))` `F_(2)=(Gm_(1)m_(2))/(R^(2))` Here, `M_(1)=4m_(1),M_(2)=4m_(2)` and R = 2r `therefore F_(2)=(G(4m_(1))(4m_(2)))/((2r)^(2))` `=(16Gm_(1)m_(2))/(4r^(2))` `therefore F_(2)=4F_(1)` Hence, the gravitational force will increase to four times the initial magnitude. |
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