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If the maximum speed and acceleration of a partical executing SHM is `20 cm//s and 100 cm//s`, find the time period od oscillation. |
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Answer» Given `|nu_(max)| = a omega = 20 cm//s` (i) and `|f_(max)| = a omega^(2) = 100 pi cm//s^(2)` (ii) Dividing Eq. (ii) by Eq. (i), we get `omega = 5 pi rad//s` Therefore, time period `T = (2 pi)/(omega) = (2 pi)/(5 pi) = 0.4 s` |
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