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If the mean deviation about the median of the numbers a, `2a, ....., 50a` is `50,` then |a| equals : (1) 2 (2) 3 (3) 4 (4) 5 |
Answer» `bar (.x) = (a + 2a + 3a + ......+ 50a)/50 ` `= (a + 50a)^(50/2)/50 = 51/2a = 25.5 a` `MD =(sum_(i=1)^n |x_i - 25.5a|)/n` `= (a+49a)^(25/2)/50 = (50a xx 25)/(2 xx50)` `= (25a)/2= 50` `a = (50 xx 2) /25` `= 4 ` option 3 is correct |
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