

InterviewSolution
Saved Bookmarks
1. |
If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is(A) (1000/√2π).e-25(B) 1000/√2π(C) (1000/√2π ).e-2.5(D) 400/√2π |
Answer» | |