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If the mean of the distribution is 2.6, then the value of y is `{:("Variate x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}`A. 24B. 13C. 8D. 3 |
Answer» Correct Answer - C Mean`=(underset(i=1)overset(n)(sum f_(i)x_(i)))/(underset(i=1)overset(n)(sum f_(i)))` `therefore 2.6=(1xx4+2xx5+3xxy+4xx1+5xx2)/(4+5+y+1+2)` `implies 31.2+2.6y=28+3y` `implies 0.4y=3.2` `implies y=8` |
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