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If the middle term in the binomial expansion of `(1/x+xsinx^(10))`is equal to `(63)/8,`find the value of `xdot` |
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Answer» `(1/x+xsinx)^10` Middle term in the above expansion `= 10/2 +1 = 6` Then, `T_6 = C(10,5)(1/x)^5(xsinx)^5` `=> 63/8 = (10*9*8*7*6)/(5*4*3*2*1)sin^5x` `=>1/8 = 4sin^5x` `=>sin^5x = 1/32` `=>sinx = 1/2` `=>x = pi/6`General value for `x = npi+(-1)^npi/6, n in Z.` |
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