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If the midpoint of the chord of the ellipse `x^2/16+y^2/25=1`is `(0,3)` |
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Answer» The equation of the chord chose midpoind is (0,3) is `(3y)/(25)-1=(9)/(25)-1` i.e., y=3 It intersects th ellipse `(x^(2))/(16)=(y^(2))/(25)=1` `:. (x^(2))/(16)=1-(9)/(25)=(16)/(25) or x=+-(16)/(3)` `:.` Length of chord `=(32)/(5)` |
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