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If the minimum wavelength of Balmer series is lamda_(1) and the maximum wavelength of Lyman series is lamda_(2), then ...... |
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Answer» `lamda_(2)=3lamda_(1)` `(1)/(lamda_(1))=R[(1)/(2^(2))-0]` `:.lamda_(1)=(4)/(R)"".........(1)` For maximum wavelength of Lyman series n = 2 `:.(1)/(lamda_(2))=R[(1)/(1^(1))-(1)/(2^(2))]=R[(1)/(1)-(1)/(4)]=R[(3)/(4)]` `:.lamda_(2)=(4)/(3R)""......(2)` `:.(lamda_(1))/(lamda_(2))=(4XX)/(R)xx(3R)/(4)=3"":.lamda_(1)=3lamda_(2)` |
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