InterviewSolution
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InterviewSolution
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If the molecular weight of two gases are `M_(1)` and `M_(2)` then at a temperature the ratio of rms velocity `C_(1) and C_(2)` will beA. `(M_(1)/M_(2))^(1//2)`B. `(M_(2)/M_(1))^(1//2)`C. `((M_(1)-M_(2))/(M_(1)+M_(2)))^(1//2)`D. `((M_(1)+M_(2))/(M_(1)-M_(2)))^(1//2)` |
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Answer» Correct Answer - B As `(1)/(2)Mc^(2)=(3)/(2)RT" or " c=((3RT)/(M))^(1//2)rArrcprop(1)/(sqrtM)` `"So"," " (c_(1))/(c_(2))=(M_(2)/(M_(1)))^(1//2)` |
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