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If the moment of a magnet is 0.4 A-m^(2) and force acting on each pole in a uniform magnetic field of induction 3.2 xx10^(-5) Wb//m^(2) is 5.12 xx 10^(-5) N, then find the distance between the poles of the magnet. |
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Answer» Solution :Magnetic moment of the magnet , `M=0.4A-m^2` Magnetic field of induction , `B=3.2 xx 10^(-5)Wb // m^(2)` Force acting on the each pole of the bar magnet , `F= 5.12 xx 10^(-5)N` Pole STRENGTH of the magnet, `m=(F)/(B) = (5.12 xx 10^(-5))/(3.2 xx 10^(-5)) = 1.6 A-m` Distance BETWEENTHE poles of the magnet ( or ) length of the magnet , ` 2l = (M)/(m) = (0.4)/(1.6) = 0.25 m = 25 cm` |
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