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If the momentum of a body is increased by 100%, then the percentage increase in the kinetic energy is A) 150%B) 200%C) 225%D) 300% |
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Answer» D) 300% Explanations: p'=100% x p+p =2p K'=(p')2 /2m =4p2 /2m 4K= 3K + K =300% K + K KE becomes four times. It means that the kinetic energy increases by 300%. |
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