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If the momentum of a body is increased by 20%, find the increase in kinetic energy. |
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Answer» SOLUTION :`K=P^2/(2M),K^1=(((120p)/(100))/(2m))^2=1.44 p^2/(2m)=1.44 k` THEREFORE DeltaK=K^1-K=0.44K=44%` |
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