InterviewSolution
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InterviewSolution
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If the momentum of an electron is changed by `Delta p` , then the de - Broglie wavelength associated with it changes by `0.50 %`. The initial momentum of the electron will beA. `(Delta p)/(200)`B. `(Delta p)/(199)`C. `199 Delta p`D. `400 Delta p` |
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Answer» Correct Answer - C `lambda = (h)/(p) rArr lambda - (0.5)/(100) lambda = (h)/( p + Delta p)` `rArr (199 lambda)/(200) = (h)/(p + Delta p) = (199)/(200) (h)/(p)` `rArr p + Delta p = (2000)/(199) p rArr p = 199 Delta p` |
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