1.

If the momentum of electron is changed by p_(m) then the de-Broglie wavelength associated with it changes by 0.50%. The initial momentum of electron will be :

Answer»

`400p_(m)`
`200p_(m)`
`(p_(m))/(200)`
`(p_(m))/(400)`

Solution :`p=(Deltap_(m))/(LAMBDA)DELTAL=(p_(m))/(200)"here" (Delta lambda)/(lambda)=(0*5)/(100)=(1)/(200)`


Discussion

No Comment Found

Related InterviewSolutions