1.

If the nuclear radius of ""^(27)Al is 3.6 fermi, the approximate nuclear radius of ""^(64)Cu is

Answer»

2.4
1.2
4.8
3.6

Solution :`R_(Al)/R_(CU)=(27)^(1//3)/(64)^(1//3)=3/4`
`R_(Cu)=4/3R_(Al)=4/3xx3.6` fermi
`R_(Cu)`=4.8 fermi


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