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    				| 1. | If the number of atoms in the domain in ferromagnetic iron, in the form of a cube of side length 1μm, is 8.65 X 10^10 atoms and dipole moment of each iron atom is 9.27 X 10^-24 Am^2, what is the maximum Magnetization of the domain?(a) 6 X 10^5 A/m(b) 7 X 10^5 A/m(c) 8 X 10^5 A/m(d) 9 X 10^5 A/m | 
| Answer» The correct choice is (c) 8 X 10^5 A/m Best explanation: Now, we know the maximum dipole moment = N X m Mmax = 8.65 X 10^10 X 9.27 X 10^-24 = 8 X 10^-13 Am^2 Volume = (10^-6)^3 = 10^-18 m^3 Therefore, Magnetization = Mmax/ Volume = 8 X 10^-13 Am^2/10^-18 m^3 = 8 X 10^5 A/m. | |