If the oxidation potential be defined with reference to Ag |Ag^(+) half cell (for which oxidation potential is taken to be zero) , which of the following will give the correct value of oxidation potential of Cu | Cu^(2+) half cell (Given that Cu | Cu^(2+) = -0.34V and Ag | Ag^(+) = -0.80 V )

If the oxidation potential be defined with reference to Ag |Ag^(+) hal

1.	If the oxidation potential be defined with reference to Ag \|Ag^(+) half cell (for which oxidation potential is taken to be zero) , which of the following will give the correct value of oxidation potential of Cu \| Cu^(2+) half cell (Given that Cu \| Cu^(2+) = -0.34V and Ag \| Ag^(+) = -0.80 V )
Answer» `-0.46` VOLTS `-1.14` volts `1.14` volts 0.46 volts Solution :For the cell reaction , `Cu + 2 Ag ^(+) to Cu^(2+) + 2 Ag` `E_(cell)^(@) = E_(Ag^(+) \|Ag)^(@) - E_(Cu^(2+)\|Cu)^(@)` = `0.80 - 034 = 0.46` V . This is the difference of reduction POTENTIALS of Ag and Cu electrodes . Taking ELECTRODE potential of Ag = 0 and `E_(Cu^(2+)\| Cu)^(@) = - 0.46` V or `therefore E_(Cu\| Cu^(2+))^(@) = 0.46` V .