1.

If the partition is removed the average molar mass of the sample will be (Assume ideal behaviour).

Answer»

`1/2` g/mol
`10/3` g/mol
`3/2` g/mol
`5/3` g/mol

Solution :`:.` We KNOW `PV=nRT`
`:.N=(RT)/(PV)`
Moles of `H_(2)=(3xx16.42)/(0.0821xx300)=2`
Moles of `D_(2)=(6xx16.42)/(0.0821xx300)=4`
AVERAGE moleclar weight `=(2xx2+4xx4)/(4+2)=10/3`


Discussion

No Comment Found

Related InterviewSolutions