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If the perimeter of e circle and square are equal,than the ratio of their areas will be equal |
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Answer» perimeter of circle = 2π r perimeter of SQUARE = 4a a = diameter of circle (d) so, πd = 4a RATIO of areas, π r^2 : d^2 (because, a = d) ---------- (1) r = d/2 substituting, r value in π r^2, we get, π × (d/2)^2 = π × d^2/4 now, from (1) π d^2/4 : d^2 so, π d^2/4 ÷ d^2 = π d^2/4 × 1/d^2 (where, d^2 will get cancelled) = π/4 × 1 -------- (2) substituting π value in (2), = 22/7 ÷ 4 = 22/7 × 1/4 = 22/28 (USING 2 as the common divisor, we DIVIDE 22 and 28 to get 11 and 14 respectively) =11/14 therefore, ratio of areas = 11 : 14 *** hope it helps ^_^if so plz mark me brainliest tyvm!!!!! |
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