1.

If the position vector of a particle is vecr=(3hati+4hatj) meter and Its angular velocity is vecomega(hatj+2hatk) rad/sec then find its linear velocity(in m/s)?

Answer»

SOLUTION :`vecv=vecomegaxxvecr=(3hati+4hatj+0hatk)XX(0hati+hatj+2hatk)=8hati-6hatj+3hatk`.


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