1.

If the potential energy of a spring is `V` on stretching it by `2cm`, then its potential energy when it is stretched by `10cm` will beA. `(V)/(25)`B. `5V`C. `(V)/(5)`D. `25V`

Answer» Correct Answer - D
`U=(1)/(2)((YA)/(L))l^2`
`because` `Upropl^2`
`(U_2)/(U_1)=((l_2)/(l_1))^2=((10)/(2))^2impliesU_2=25U_1`
i.e., potential energy of the spring will be `25V`


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