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If the power factor is `1//2` in a series `RL` circuit with `R = 100 Omega`. If `AC` mains, `50 Hz` is used then `L` isA. `(sqrt(3))/(pi)` henryB. `pi` henryC. `sqrt(3)` henryD. `sqrt(3) pi` henry |
Answer» Correct Answer - A `Z = sqrt(R^(2) + omega^(2) L^(2))` `cos phi = (R )/(2) implies (1)/(2) = (100)/(2) implies Z = 200 Omega` `:. R^(2) + omega^(2) L^(2) = Z^(2) implies omega^(2) L^(2) = Z^(2) - R^(2)` `implies omega^(2) L^(2) = 4 xx 10^(4) - (100)^(2) = 3 xx 10^(4) implies omega L = 100 sqrt(3)` `implies 2 xx pi xx 50 xx L = 100 sqrt(3) implies L = (100 sqrt(3))/(2 pi xx 50) = (sqrt(3))/(pi)` |
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