1.

if the present ages of a&b are in the ratio of 9:4 and after 7 years there ages are in the ratio of5:3 then find there present age​

Answer»

-The present AGES of a & b are in the RATIO of 9:4.After 7 YEARS there ages are in the ratio of 5:3.To find :-Their present AGE.Solution :-✪The present ages of a & b are in the ratio of 9:4.✪Let the present age of a be 9X years and the present age of b be 4x years.★ After 7 years,Age of a = (9x+7) yearsAge of b = (4x +7) years✪After 7 years there ages are in the ratio of 5:3✪According to the question,•Present age of a = 9×2 = 18 years•Present age of b = 4×2 = 8 yearsTherefore, present age of a is 18 years and present age of b is 8 years._____________________Verification :-• Present age of a = 18 years.• Present age of b = 8 years.Ratio of their present ages =9:4→ 18 : 8 = 9 : 4→ 9 : 4 = 9 : 4 (Verified )________________



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