1.

If the pressure of N, and H, mixture in a closedapparatus is 100 atm and 20% of the mixturereacts then the pressure at the same temperaturewould be(1) 100(3) 850.(2) 90(4) 80

Answer»

N2+3H2=2NH3; As we know N2+H2=100atm then; Partial pressure of N2 &H2 be pN2 +p3H2=P +3P=4P 4P=100P=25 as we know 20% mixture react means α=.2 Acc.to Formula, α=x÷P; x=5 So, N2+3H2=2NH3 Intially. 25 75 0 At Eq. 25-x 75-3x 2x 25-5 75-15 2(5) 20 60 10 P=20+60+10=90



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