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If the probability distribution of a random variable X is as given below Then, mean and variance are A. `4/5 and (54)/(25)`B. `4/(10) and (54)/(25)`C. `4/(15) and (27)/(25)`D. None of these |
Answer» Correct Answer - A The given distribution is a probability distribution `thereforeP(x=-2)+P(x=-1)+P(x=0)+P(x=1)+P(x=2)+P(x=3)=1` `rArr" "1/(10)+k+1/5+2k+3/(10)+k=1` `" "4k=4/(10)` `rArr" "k=1/(10)` Mean `=1/(10)-(-2)+k(-1)+1/5(0)+2k(1)+3/(10)(2)+k(3)` `=-2/(10)-k+0+2k+6/(10)+3k` `=4/(10)+4k=4/(10)+4xx1/(10)` `=8/(10)=4/5` Variance `=1/(10)(-2)^2+k(-1)^2+1/5(0)^2+2k(1)^2+3/(10)(2)^2+k(3)^2-("mean")^2` `=4/(10)+k+0+2k+(12)/(10)+9k-(4/5)^2` `=(16)/(10)+12k-(16)/(25)=(16)/(25)+12xx1/(10)-(16)/(25)=(54)/(25)` |
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