1.

If the product of the zeroes of the quadratic polynomial 3x² + 5x + k is -2/3 , thenk = -3k = -2 k = 2k = 3

Answer»

Answer:

K = -2

Step-by-step explanation:

Given :

The product of the zeroes of the quadratic polynomial 3x² + 5x + k is -2/3

To find :

the value of k

Solution :

3x² + 5x + k

  • x² coefficient = 3
  • x coefficient = 5
  • CONSTANT term = k

From the relation between zeroes and coefficients of the quadratic equation :

Product of zeroes = constant term/x² coefficient  

 \sf \dfrac{-2}{3}=\dfrac{k}{3} \\\\ \sf k=\dfrac{-2}{3} \times 3 \\\\ \sf k=-2

THEREFORE, the value of k is -2

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About Quadratic Polynomial :    

✯ It is a polynomial of degree 2    

✯ General form :    

 ax² + bx + c  = 0    

✯ Determinant, D = b² - 4ac    

✯ Based on the value of Determinant, we can DEFINE the nature of roots.    

D > 0 ; real and unequal roots    

D = 0 ; real and equal roots    

D < 0 ; no real roots i.e., imaginary    

✯ Relationship between zeroes and coefficients :    

✩ Sum of zeroes = -b/a    

✩ Product of zeroes = c/a    

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