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If the quadratic equation is (x-a) (x-b) + (x-b) (x-6) + (x-c) (x-a)=0 equal then show that a = b = c |
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Answer» quadratic equation is (x-a) (x-B) + (x-b) (x-c) + (x-c) (x-a)=0equal then show that a = b = c─━─━─━─━─━─━─━─━─━─━─━─━─☆ Its a quadratic equation, it implies☆Since, quadratic equation has equal roots.☆ Therefore, DISCRIMINANT = 0☆ MULTIPLY by 2 on both sides, we get☆ Since, SUM of squares = 0─━─━─━─━─━─━─━─━─━─━─━─━──━─━─━─━─━─━─━─━─━─━─━─━─ |
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