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If the quadratic function f(x) = 3x² + 12x - 5, is expressed in the form f(x) = 3(x-p)² + q, where p and q are constants, find the value of p and of q.Answer:​

Answer»

3(x-p)² + Q,f(x) = 3(x² - 2px + p²)+ q,f(x) = 3x² - 6px + 3p²+ q,but f(x) = 3x² + 12X - 5, (GIVEN) so, by comparing them,we get-6p = 12 and 3p²+ q = - 5solving them,we get p = - 2 and q = - 17


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