current density must be 1/4 times to maintain the same current along the axis of the cylinder..

to maintain the same current , current density decreases 1/4 times

Current density= Current/Perpendicular area

For a cylinder, area= πr^2If radius is doubled, area becomes four times.

So current density must become one fourth of its value to maintain same current.

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current density must be 1/4 times to maintain the same current along the axis of the cylinder

current density must be 1/4 times to maintain the same current along the axis of the cylinder

current density must be 1/4 times to maintain the same current Along the axis of the cylinder

current density must be 1/4 times to maintain the same current along the axis of the cylinder

1/4 times########*********, *,,

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Current Density becomes 1/4 times to maintain the same current

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current density must be 1/4 times to maintain the same current along the axis of cylinder

The refraction index of a glass prism is situated a minimum deviation position show that the angle of minimum deviation dm=180-2A where A is the angle of prism?

to maintain the same current , current disitu decreases 1/4 times. is the correct answer.

current density must be 1/4 times to maintain the same current along the axis of the cylinder

current density should be one fourth times to maintain the same current along the axis of the cylinder

current density must be 1/4 times to maintain the same current along the axis of the cyclinder

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current density must be 1 upon 4 to maintain the same current along the axis of the cylinder .it is the correct answer

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it will be 1/4 times

1/4 is the correct answer

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current density must be 1/4 times to maintain the same current along the axis of the cylinder.

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I think 1/4 is the current density along the axis of the cylinder.

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to maintain the same current, current density decreases 1/4 times this is right answer

1/4 the current density must have to

Current Density should be one-fourth times ( 1/4 times) to maintain the same current.

current density j=i/A and A=pi r^2so i=j. A i=j. pi r^2if radius doubled i=j. pi (2r)^2i=j. 4pi r^2hence in order to maintain same current the current density j has to become one-fourth of its original value

Current density is double

1/4is a right answer after calculate the sum answer is 1/4

current density must (1/4) times.

current density must be 1/4times to maintain the same current along the axis of the cylinder

current density must be 1/4 times to maintain the same current along the axis of the cylinder

1/4 is the right answer of the following

To maintain the same current, current density decreases 1/4 times

decrease current density by factor of 4

1/4 should be the current density

current density must be one by fourth X to maintain the same current along the axis of the cylinder

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curre turn density must be burned by 4 times to maintain the same current and Andy excessively cylinder

current density must be one by four times to maintain the same current along the axis of the cylinder

the correct answer is to maintain the same current , current density decreass 1/4 times

current density must be 1/4 times to maintain the same current along the axis of the cylinder

current density must be 1/4 times to maintain the same current along the axis of cylinder

current density must be 1/4 times to maintain the same current along the axis of the cylinder

1/4 is the right answer of the following

The current density must be 1/4 times to maintain the same current along the axis of the cylinder

current density most be 1/ 4 times to maintain the same current along the axis of the cylinder

To maintain the same current,current density decrease 1/4 times

If you want to maintain same current then you have to decreased current by 4x.

current density must be 1/4 times to mantain the same current

to maintain the same current, current density decreases 1/4 times

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current density become 1/4 times

1/4 time in orderto maintaining the same current

1/4 is the correct answer

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current density must be 1/4 times to maintain the same current along the axis of the cylinder

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1/4 is the right answer

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current density must be 1/4timed

current dencity must be 1/4 times to maintain the same current along the axis of the cylinder

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current density must be 1/4 times to maintain the same current along the axis of the cylender

Your correct answer is 1/4

to maintain the same current, current density 1/4 times

1/4 is the right answer of the following

to maintain the same current, current density decreases 1/4 times

current density must be 1/4 times to maintain the same current along axis of cylinder

to maintain the same current the density should be 1/4 along the axis of the cylinder

current density must be 1/4 time to maintain the same current along the axis of the cylender

same current along the axis of the

current density must be 1/4times maintain the same current along the axis of the cylinder

1/4times current density changes

Current density=current÷perpendicular area

for a cylinder, area=πr²if radius is doubled,area becomes four times.

So current density must become one fourth of its value to maintaion same current

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current density must be 1/4 times to maintain the same current along the axis of the cylinder

J=I/A so j= 1/4 time to maintain same current

1/4 times current density changes

current density must be 1/4 times to maintain the same current along the axis of cylinder

density decreses 1/4 times

if r doubles the j must be 1/4 times changed in order to maintain the same current

to maintain the same current density decrease 1/4 times

1÷2 or half is the answer

current density becomes 4 times is the correct answer for this question

current density must be 1/4 times to maintain the same current along the axis of the cylender

current density must be 1/4 times to maintain the same current along the axis of the cy cylender

current denusity must be 1/4 times to maintain the same current along the axis of the cylinder it is the correct answer of the following question

The current density acrossa cylindrical conductor of radius R varies ... dA= 2pi*rdr considering it is a cylinder, so consider a ring ... On integrating we get I=J0*pi*R2/3.

Above answers are absolutely correct...

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