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If the radius of a planet is R and its density is `rho` , the escape velocity from its surface will beA. `v_(e) prop R sqrt(rho)`B. `v_(e) prop (1)/(sqrt(rhoR))`C. `V_(e) prop rhoR`D. `V_(e) prop (sqrt(rho))/( R)` |
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Answer» Correct Answer - A `v_(e)=sqrt((2GM)/(R ))=sqrt((2G.(4)/(3)pi R^(3)rho)/(R ))` `= sqrt((8)/(3)G pi rho R^(2))=2R sqrt((2)/(3)G pi rho)` Thus `v_(e) prop R sqrt(rho)` `because` The remaining quantities are constant. |
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