InterviewSolution
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InterviewSolution
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If the radius of earth is 6400km, calcu late (a) angu lar velocity (b) linear velocity and (c) radial accelration for a point on its equator considering its spin motion alone. What will be the values of above quantities if the pint is at the pole? |
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Answer» As earth makes one rotation on its axis every 24hrs- (a) `omega_(s)=(2pi//T)=(2pi//24xx60xx60)=7.3xx10^(-5)` rad/s (b) `v=4omega=(6.4xx10^(6))(7.3xx10^(-5))=4.7xx10^(2)m//sapprox0.5` km/s (c) `a_(r)=romega^(2)=(6.4xx10^(6))(7.3xx10^(-5))^(2)=3.4xx10^(-2)m//s^(2)` Now, if the point is at pole, `r rarr0` so `v=(romega)` and `a_(r)(=romega^(2))` will become zero while `omega` (chracteristic of rigid body ) will remain unchanged. |
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