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If the radius of sphere is incresed 10%, by how much % will its volume increase |
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Answer» -step explanation:LET the radius of SPHERE be 'R+(r/10)'Volume of sphere=(4/3)π(r+(r/10))^3 =(4/3)(22/7)(11r/10)^3 =(4/3)(22/7)(1331r^3/1000) Volume of a normal sphere =(4/3)π(r)^3Comparison= {(4/3)(22/7)(1331r^3/1000)} / {(4/3) (22/7)(r)^3} = {(1331r^3/1000) × (1/r^3)} = {(1331r^3/1000r^3)} = 1.331 % |
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