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If the radius of the bromide ion is 0.182 nm, how large a cation can fit in each of the tetrahedral holes ? |
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Answer» `:. r_(+)` (radius of tetrahedral hole) = `0.225 xx r_(-) =0.225 xx 0.182 NM= 4.01 xx 10^(-2)` nm Therefore, CATION having radius of `4.01 xx 10^(-2)` nm will just FIT in the tetrahedral hole. |
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