1.

If the radius of the circular base of a right circular cone is tripled, find the ratio of the volume of the first one to that of the second, the height remaining same.​

Answer»

Suppose thatRadius of the base is r, and the height of the original cone is h.Then,VOLUME of the original cone (V 1 )= 31 πr 2 HWHEN cone REDUCED then, radius = 2r height =hNow,Volume of the reduced cone (V 2 )= 31 π( 2r ) 2 h = 41 ( 31 πr 2 h) = 41 V 1 $$ ∴ V 1 V 2 = 41 =1:4



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