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If the radius of the earth is 6400 km, the height above the surface of the earth where the value of acceleration due to gravity will be `4%` of its value on the surface of the earth isA. 6400 kmB. 64 kmC. 57600 kmD. 25600 km |
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Answer» Correct Answer - d `(g_(h))/(g)=((R)/(R+h))^(2)` `(4)/(100)=((R)/(R+h))^(2)` `(1)/(5)=(R)/(R+h)` `R+h=5R` `h=4R=4xx6400=25600km`. |
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