InterviewSolution
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InterviewSolution
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If the radius of the earth was to shringk by 2% its mass remaining same the acceleraton due to gravity on the earth surface would beA. decrease by 2%B. increased by 2%C. incresed by 4%D. decrease by 4% |
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Answer» Correct Answer - C As `Gg=(GM)/(R^(2))` if R decreases then g increases taking logarithm of both the sides we get `log g = log G+log M -2 log R` Differentaiting it we get `(dg)/(g)=0 +0-(2dR)/(r )=-2(-2)/(100)=(4)/(100)` ` therefore` % increasing in `g=(dg)/(g)xx100=4/100xx100=4%` |
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