1.

If the range of a gun which fires a shell with muzzle speed ν is R, then the angle of elevation of the gun is :-

Answer»

`cos^(-1)(v^2/(Rg))`
`cos^(-1)((Rg)/v^2)`
`1/2sin^(-1)(v^2/(Rg))`
`1/2 sin^(-1)((Rg)/v^2)`

Solution :`R=(v^2 sin 2theta)/G` or `sin 2 THETA =(gR)/v^2`
`therefore theta=1/2 sin^(-1) ((gR)/v^2)`


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