1.

If the rate constant of a reaction at 600K is 100 times the rate constant at 500K, then the value of the activation energy obtained by Transition state theory is ____(a) 120987.12(b) 167435.15(c) 110319.28(d) 156435.54The question was posed to me during an interview for a job.The origin of the question is Kinetics of Homogeneous Reactions in chapter Kinetics of Homogeneous Reactions of Chemical Reaction Engineering

Answer»

The correct choice is (c) 110319.28

For explanation: By Transition state theory, LN(\(\frac{k_2}{k_1}) = -\frac{E}{R} (\frac{1}{T_2} – \frac{1}{T_1}) + ln(\frac{T_2}{T_1}) \)

ln(\(\frac{100k_1}{k_1}) = -\frac{E}{8.314} (\frac{1}{600} – \frac{1}{500}) + ln(\frac{600}{500}) \)

E = 110319.28.



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