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The equation representing the variation of rate constant with respect to temperature by Arrhenius equation is ____(a) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}(\frac{1}{T_2} – \frac{1}{T_1}) \)(b) ln(\(\frac{k_2}{k_1}\)) = \(\frac{E}{R}(\frac{1}{T_2} – \frac{1}{T_1}) \)(c) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}(\frac{1}{T_1}- \frac{1}{T_2}) \)(d) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}(\frac{1}{T_2} + \frac{1}{T_1}) \)I had been asked this question in semester exam.Asked question is from Kinetics of Homogeneous Reactions topic in portion Kinetics of Homogeneous Reactions of Chemical Reaction Engineering

Answer»

The correct answer is (a) ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}(\frac{1}{T_2} – \frac{1}{T_1}) \)

For EXPLANATION I would say: By Arrhenius equation, k = \(Ae^{\frac{-EA}{RT}},\) where A is the frequency factor.

For TWO different temperatures, T1 and T2, the Arrhenius equation is reduced as ln(\(\frac{k_2}{k_1}\)) = –\(\frac{E}{R}(\frac{1}{T_2} – \frac{1}{T_1}). \)



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