1.

If the rate of a reaction is 5 at 10^(@)Cthen onincreasing the temperature to 30^(@)C , new rate is

Answer»

20
10
50
40

Solution :For every `10^(@)` RISE of temperature rate CONSTANT doubles .
For `20^(@)` rise of temperature , rate constant becomes 4 TIMES ,
i.e., `k_(2) = 4k_(1) = 4 xx 5 = 20.`


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