1.

If the rate of deactivation is given by –\(\frac{da}{dt}\) = 0.0064 day^-1, the expression relating activity and time is ___(a) a = 0.0064t(b) a = 1-0.0064t(c) a = t(d) a = 0.0064-tThe question was posed to me at a job interview.My question is based upon Mechanisms of Catalyst Deactivation topic in division Suspended Solid Reactors, Catalyst Deactivation, Diffusion and Reaction of Chemical Reaction Engineering

Answer»

The CORRECT OPTION is (b) a = 1-0.0064t

The EXPLANATION is: –\(\FRAC{da}{dt}\)= 0.0064

–\(\int_1^a\)da = 0.0064\(\int_0^t\)dt

Integrating, a = 1-0.0064t



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