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If the ratio of amplitude of two waves is `4:3`, then the ratio of maximum and minimum intensity isA. `16:18`B. `18:16`C. `49:1`D. `1:49` |
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Answer» Correct Answer - C In the interference pattern, `I_("max")=(a+b)^(2)and I_("min")=(a-b)^(2)` `(I_("max"))/(I_("min"))=((a+b)^(2))/((a-b)^(2))=((4+3)^(2))/((4-3)^(2))` `((7)/(1))^(2)=(49)/(1)=49:1` |
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