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If the ratio of specific heat of a gas of constant pressure to that at constant volume is `gamma`, the change in internal energy of the mass of gas, when the volume changes from `V` to `2V` at constant pressure `p` is |
Answer» `dU=nC_(v)dT=n(R)/(gamma-1)dT=n(PdV)/(gamma-1)` `=n(p(2V-V))/(gamma-1)=(PV)/(gamma-1)` |
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